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y^2+44y+44=0
a = 1; b = 44; c = +44;
Δ = b2-4ac
Δ = 442-4·1·44
Δ = 1760
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1760}=\sqrt{16*110}=\sqrt{16}*\sqrt{110}=4\sqrt{110}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-4\sqrt{110}}{2*1}=\frac{-44-4\sqrt{110}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+4\sqrt{110}}{2*1}=\frac{-44+4\sqrt{110}}{2} $
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